Sometimes you may want to convert a macro argument into a string
constant. Parameters are not replaced inside string constants, but you
can use the #
preprocessing operator instead. When a macro
parameter is used with a leading #
, the preprocessor replaces it
with the literal text of the actual argument, converted to a string
constant. Unlike normal parameter replacement, the argument is not
macro-expanded first. This is called stringification.
There is no way to combine an argument with surrounding text and stringify it all together. Instead, you can write a series of adjacent string constants and stringified arguments. The preprocessor will replace the stringified arguments with string constants. The C compiler will then combine all the adjacent string constants into one long string.
Here is an example of a macro definition that uses stringification:
#define WARN_IF(EXP) \ do { if (EXP) \ fprintf (stderr, "Warning: " #EXP "\n"); } \ while (0) WARN_IF (x == 0); ==> do { if (x == 0) fprintf (stderr, "Warning: " "x == 0" "\n"); } while (0);
The argument for EXP
is substituted once, as-is, into the
if
statement, and once, stringified, into the argument to
fprintf
. If x
were a macro, it would be expanded in the
if
statement, but not in the string.
The do
and while (0)
are a kludge to make it possible to
write WARN_IF (
arg);
, which the resemblance of
WARN_IF
to a function would make C programmers want to do; see
Swallowing the Semicolon.
Stringification in C involves more than putting double-quote characters
around the fragment. The preprocessor backslash-escapes the quotes
surrounding embedded string constants, and all backslashes within string and
character constants, in order to get a valid C string constant with the
proper contents. Thus, stringifying p = "foo\n";
results in
"p = \"foo\\n\";". However, backslashes that are not inside string
or character constants are not duplicated: \n
by itself
stringifies to "\n".
All leading and trailing whitespace in text being stringified is ignored. Any sequence of whitespace in the middle of the text is converted to a single space in the stringified result. Comments are replaced by whitespace long before stringification happens, so they never appear in stringified text.
There is no way to convert a macro argument into a character constant.
If you want to stringify the result of expansion of a macro argument, you have to use two levels of macros.
#define xstr(s) str(s) #define str(s) #s #define foo 4 str (foo) ==> "foo" xstr (foo) ==> xstr (4) ==> str (4) ==> "4"
s
is stringified when it is used in str
, so it is not
macro-expanded first. But s
is an ordinary argument to
xstr
, so it is completely macro-expanded before xstr
itself is expanded (see Argument Prescan). Therefore, by the time
str
gets to its argument, it has already been macro-expanded.